Our students hydrate 1-hexene to make 2-hexanol, illustrating Markovnikov's rule. Though it isn't apparent from their data (bp and 1H/13C NMR spectra), we tell them the main product is a racemic mixture of (R)- and (S)-2-hexanol. We describe here an experiment for students to prove this by reacting their alcohol with a chiral auxiliary. Mosher's acid chloride is often used for this in industry but is too expensive for a large class. An affordable chiral reagent is the chloride of (1R)-(-)-10-camphorsulfonic acid (CSA). Few alkyl esters of CSA are described in the literature and these are made using metal alkoxides. We deemed that unsuitable for our students. A procedure was developed where the reactants are mixed with triethylamine in CH2Cl2 to produce the desired CSA esters of (R)-2-hexanol [1] and (S)-2-hexanol [2]. These differed by 0.11 ppm at C-2 of the hexyl group in the 13C NMR spectrum. Authentic (R)-2-hexanol was converted to 1 and used to identify the diastereomers. The C-2 chemical shift of 1 was less than that of 2. Calculations, using Gaussian, predicted this result correctly. The rearranged product 3-hexanol is formed also and it can be shown to be a racemate by making its CSA ester. Supported in part by a Faculty Research Grant from the Fordham University Research Council.